Some times ago I was working on the project with JSON call and at the time my requirement to pass some data from outside by variables in the JSON. I tried various ways to pass data but did not find any success, I have also google multiple sites and blogs but not able to find the solution. finally I got the solution after some hidden trial.
There are two ways to pass the data in JSON
1- Pass data as Array
var arr = {};
arr.FetchXML = fetchXml;
arr.LayoutXML = layoutXml;
arr.EntityName = entityName;
arr.DefaultAdvFindViewId = defaultAdvFindViewId;
arr.ViewType = 1039;
arr.SortCol = sortCol;
arr.SortDescend = sortDescend;
$.ajax({
type: "POST",
contentType: "application/x-www-form-urlencoded",
datatype: "json",
url: url,
data: arr,
timeout: timeoutvalue,
beforeSend: function (XMLHttpRequest) {
//Specifying this header ensures that the results will be returned as JSON.
XMLHttpRequest.setRequestHeader("Accept", "application/json");
},
success: function (data, textStatus, XmlHttpRequest) {
PushResponseContents(iFrame, XmlHttpRequest, entityTypeId);
},
error: function (XMLHttpRequest, textStatus, errorThrown) {
//errorHandler(XMLHttpRequest, textStatus, errorThrown);
//alert(textStatus);
//alert(errorThrown);
doc.open();
doc.write("");
doc.close();
alert("Request Timeout. Please refine your search criteria");
}
});
2- Pass data as parameter
$.ajax({
type: "POST",
url: "http://" + location.hostname + "/ISV/",
data: "{\"id\":'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (response) {
// alert(response);
},
error: function (jqXHR, textStatus, errorThrown) {
//alert(jqXHR);
//alert(textStatus);
//alert(errorThrown);
}
});
Note: If this blog help to find/resolve your query then please comment.
There are two ways to pass the data in JSON
1- Pass data as Array
var arr = {};
arr.FetchXML = fetchXml;
arr.LayoutXML = layoutXml;
arr.EntityName = entityName;
arr.DefaultAdvFindViewId = defaultAdvFindViewId;
arr.ViewType = 1039;
arr.SortCol = sortCol;
arr.SortDescend = sortDescend;
$.ajax({
type: "POST",
contentType: "application/x-www-form-urlencoded",
datatype: "json",
url: url,
data: arr,
timeout: timeoutvalue,
beforeSend: function (XMLHttpRequest) {
//Specifying this header ensures that the results will be returned as JSON.
XMLHttpRequest.setRequestHeader("Accept", "application/json");
},
success: function (data, textStatus, XmlHttpRequest) {
PushResponseContents(iFrame, XmlHttpRequest, entityTypeId);
},
error: function (XMLHttpRequest, textStatus, errorThrown) {
//errorHandler(XMLHttpRequest, textStatus, errorThrown);
//alert(textStatus);
//alert(errorThrown);
doc.open();
doc.write("");
doc.close();
alert("Request Timeout. Please refine your search criteria");
}
});
2- Pass data as parameter
$.ajax({
type: "POST",
url: "http://" + location.hostname + "/ISV/",
data: "{\"id\":'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (response) {
// alert(response);
},
error: function (jqXHR, textStatus, errorThrown) {
//alert(jqXHR);
//alert(textStatus);
//alert(errorThrown);
}
});
Note: If this blog help to find/resolve your query then please comment.
2 comments:
Great Information.it was very much useful.
Thanks for posting such an article.
keep sharing.
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